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McVoodoo
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Subject: ANSWER

4*k+4*q+4*j=12
there can be:
4*k+4*q+4*j+1a+1*10=14
4*k+4*q+4*j+1a+2*10=15
4*k+4*q+4*j+1a+3*10=16
4*k+4*q+4*j+1a+4*10=17
4*k+4*q+4*j+2a+1*10=15
4*k+4*q+4*j+2a+2*10=16
4*k+4*q+4*j+2a+3*10=17
4*k+4*q+4*j+2a+4*10=18
4*k+4*q+4*j+3a+1*10=16
4*k+4*q+4*j+3a+2*10=17
4*k+4*q+4*j+3a+3*10=18
4*k+4*q+4*j+3a+4*10=19
4*k+4*q+4*j+4a+1*10=17
4*k+4*q+4*j+4a+2*10=18
4*k+4*q+4*j+4a+3*10=19
4*k+4*q+4*j+4a+4*10=20

That means 14, 15, 16, 17, 18, 19, 20 it can be (assuming that deck was only cut, not shuffled)

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Time Posted:	April 12 2010 03:30 am EDT
Last updated:	April 13 2010 04:29 pm EDT

Replies:

Incorrect - Ninja_Gopher
have you looked at this? - McVoodoo

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