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| Cronos
Posts: 297 Status: Viscount Karma: +34 [+1] [-1]   |
Subject: Response | |||||
| Well lets say the cards suit are ordered spade, heart, club, and diamond.Now i have made some calculation for each possibility so it is a bit long.If you dont wanna get bored just look the final numbers in the end. If 10 and A are both of same suit: 10 if u count A-10, 4 if you count 10, J, Q, K, and 5 if you count 10, J, Q, K, A. For the other cases there are 3 ways of counting: 1.A to 10 2.10 to A where A is {1,2,3} suits forward 10. During the count to the 1st suit you count only 10, J, Q, K and then the normal count. 3.Same as 2 but here, in the 1st suit count you include A so the count is 10, J, Q, K, A and then normal count. So there are only these 3 ways of counting. If A is 1 suit forward 10 it should be: 1.If counted like 1st way there should be 23 2.If counted as 2nd way there should be 17 3.If counted as 3rd way there should be 18. If A is 2 suits forward 10 1.If counted like 1st way there should be 36 cards. 2.If counted as 2nd way there should be 18. 3.If counted as 3rd way there should be 19. If A is 1st suit and 10 last suit or 3 suits forward there should be: 1.If counted like 1st way there should be 49 2.If counted as 2nd way there should be 40 3.If counted as 3rd way there should be 41 This is all by including A and 10. So the final numbers are: 5, 10, 17, 18, 19, 23, 36, 40, 41, 49. If these are incorrect then DUDE!!! |
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